Originally posted by lxlaw
Well you are right by figuring it like that, that is the only way i could rationize it also, but the teaser is trying to get them to figure it by using the $9x3 +2. But you did it the same way we have. Guess it is right.
It is right.
I saw this one long ago. It sounds tough, but it is really that simple.
The thing that throws it off is the end question. Why is there not $30? Well, forget about the $30. That number was thrown out the window when the owner realized the room was really $25. It is no longer correct to assume that anything should equal $30.
Forget the room was ever $30 in the first place. They paid ten each. They each got $1 back. That means they paid $9 each. Well, that's $27. The room was $25, so the bell boy keeps the $2 change.
Or even forget that they got a dollar back. Let's just say they started out at $9 each. They paid for the $25 room, which leaves $2 for the bell boy.
Again, the problem, and catch to this riddle is that you come in at the end and ask where the other dollar is. What other dollar? There isn't one. You trick the mind into remembering the $30 number, but that number is completely void and insignificant. The figuring is all based on how much money exchanged hands, and how much the room costs. The $30 was nothing but a simple mistake, and doesn't belong in the equation anymore.
I hope that makes sense. I think I've explained it enough.